Question: 0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The molecular weight of the acid will be [CPMT 1989]
(a) 32
(b) 64
(c) 128
(d) 256
Correct Answer: (c) 128
![Question: 0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The molecular weight of the acid will be [CPMT 1989] (a) 32 (b) 64 (c) 128 (d) 256](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgABbvDEJcjRrWfUOISckwLE-cPMmE3MO-47cyJF0YcPfSAXdYZIqMPro27-N_QlYKDSkDJ3cjwA3ReXsNRgdahrPdy0jOEZSrvNdgvdfwKmoZBXbReq24Ll7k7Pcl6igBqbhVGG60HNJBuyrntap2i0pxPf9vOi5Eika4W6ibnZU6bdLzIvS4BByFB/s1920/0.16%20g%20of%20dibasic%20acid%20required%2025%20ml%20of%20decinormal%20NaOH%20solution%20for%20complete%20neutralisation.%20The%20molecular%20weight%20of%20the%20acid%20will%20be%20%5BCPMT%201989%5D.jpg "Question: 0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The molecular weight of the acid will be [CPMT 1989] (a) 32 (b) 64 (c) 128 (d) 256")
Question: 0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The molecular weight of the acid will be [CPMT 1989]
(a) 32
(b) 64
(c) 128
(d) 256
Correct Answer: (c) 128